Back to KINETIC THEORY OF GASES

NEET UG PHYSICS MCQ: KINETIC THEORY OF GASES

1 Hard

1 of 1

Application +4 | -1

The temperature of a gas is

-78^{\circ} \mathrm{C}

and the average translational kinetic energy of its molecules is K. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes

2 \mathrm{~K}

is :

View answer and explanation

Correct option: B

117^{\circ} \mathrm{C}

Option D (Statement I is false but Statement II is true) is correct. The average momentum is zero for an ideal gas, and doubling the temperature and dissociating oxygen doubles the rms speed.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs →

The absolute zero is the temperature at which The internal energy

\left( U \right)

\left( p \right)

\left( V \right)

of an ideal gas are related as

U = 3pV + 4

. The gas is A monoatomic ideal gas is contained in a rigid container of volume

V

with walls of total inner surface area

A

x

and thermal conductivity

K

. The gas is at an initial temperature

T_0

P_0

. If the pressure of the gas as a function of time if the temperature of the surrounding air is

T_{\mathrm{s}}

\frac{T_0}{T_0}\left[T_s-\left(\mathrm{T}_s-T_0\right)_e \frac{-Z k A}{3 x R} t\right]

. Find the value of

z

. All temperatures are in absolute scale. Assertion: The change in air pressure effect the speed of sound.
Reason: The speed of sound in a gas is proportional to the square of pressure. The rms speed of oxygen molecule in a vessel at particular temperature is

\left(1+\frac{\gamma}{28}\right)^{\frac{1}{2}} v,

v

is the average speed of the molecule. The value of

\gamma

\left(\pi=\frac{22}{7}\right)

For an ideal gas the instantaneous change in pressure

p

V

is given by the equation

\frac{{dp}}{{dV}}\, = \, - ap.

p\, = \,{p_0}

V\, = \,0

is the given boundary condition, then the maximum temperature one mole of gas can attain is (Here

R

is the gas constant)