JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

One junction of a certain thermo-couple is at a fixed temperature

{T_r}

and the other junction is at temperature

T

. The thermo electric force for this is expressed by

E = K\left( {T - {T_r}} \right)\,\,[\,{T_0}\,\, + \,\,\frac{1}{2}\left( {{T^2} + T_r^2)\,} \right]

At temperature

T = {T_0}/2

the thermoelectric power is

View answer and explanation

Correct option: B

\frac{3}{2}\,\,K\,{T_0}

Option B (

\frac{3}{2}\,K\,{T_0}

) is correct because it is the thermoelectric power calculated by differentiating the given equation and substituting

T = T_0/2

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