NEET UG PHYSICS MCQ: GRAVITATION

1 Easy

1 of 1

Analyzing +4 | -1

Assertion: For a satellite revolving very near to earth's surface the time period of revolution is given by

1 \mathrm{~h} \, 24 \mathrm{~min}

.
Reason: The period of revolution of a satellite depends only upon its height above the earth's surface.

View answer and explanation

Correct option: A

Assertion is True, Reason is True; Reason is a correct explanation for Assertion

Option B (7R) is correct because the distance of a geostationary satellite from the center of the Earth is approximately 42,000 km, which is about 7 times the Earth's radius.

More Questions from GRAVITATION

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.