In $_{88}R{a^{226}}$ nucleus, there are

${\rm{138}}$ neutrons and ${\rm{88}}$ protons

${\rm{138}}$ protons and 88 neutrons

${\rm{226}}$ protons and ${\rm{88}}$ electrons

${\rm{226}}$ neutrons and ${\rm{138}}$ electrons

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JEE PHYSICS MCQ: NUCLEI

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_{88}R{a^{226}}

nucleus, there are

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Correct option: B

\mathrm{138}

neutrons and

\mathrm{88}

protons

Option B is correct because the number of protons is equal to the atomic number (88), and the number of neutrons is the mass number (226) minus the atomic number (88), which equals 138.

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