JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

1 of 1

Analyzing +4 | -1

Let

f(x)=\log (\sin x+\cos x), x \in x\left(-\frac{\pi}{4}, \frac{3 \pi}{4}\right).

Then

f

is strictly increasing in the interval

View answer and explanation

Correct option: A

\left(-\frac{\pi}{4}, \frac{\pi}{4}\right)

Option A

\left(-\frac{\pi}{4}, \frac{\pi}{4}\right)

is correct because the derivative of the function is positive in this interval, indicating that the function is strictly increasing.

More Questions from INCREASING & DECREASING

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)