JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\tan (\pi \cos x)=\cot (\pi \sin x)

, then

\cos \left(x-\frac{\pi}{4}\right)

View answer and explanation

Correct option: B

\frac{1}{2 \sqrt{2}}

Option B (

\frac{{1}}{{2 \sqrt{{2}}}}

) is correct because it is the value obtained after simplifying the given trigonometric equation and using the cosine subtraction formula.

More Questions from TRIGONOMETRIC EQUATIONS

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\left[ {0,\;\,\frac{\pi }{2}} \right]

\left( {x,\,y} \right)

x,\,\,y \in \left[ {0,10} \right]

\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

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\tan \frac{\pi}{5}+2 \tan \frac{2 \pi}{5}+4 \cot \frac{4 \pi}{5}

0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x