JEE PHYSICS MCQ: WAVES

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Two waves are given by

{y_1} = a\,\,\sin \left( {\omega t - kx} \right)

and

{y_2} = a\,\,\,\cos \left( {\omega t - kx} \right)

The phase difference between the two waves is

View answer and explanation

Correct option: D

\pi /2

Option D (

\pi /2

) is correct because the cosine function is a sine function shifted by

\pi/2

.

More Questions from WAVES

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The source of sound generating a frequency of

3\,\,kHz

reaches an observer with a speed of

0.5

times, the velocity of sound in air. The frequency heard by the observer is A source of sound emits waves with frequency

f\mathrm{ }Hz

V\mathrm{ }m/sec

. Two observers move away from this source in opposite directions each with a speed

0.2\,\,V

relative to the source. The ratio of frequencies heard by the two observers will be Assertion: The wave function of a pulse is given by

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

it propagates in

(– \mathrm{ve}) \,x

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Reason: The given wave function is of the form

y = f(kx +\omega t),

which represent a wave travelling in negative

X

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0.01\,\,s

. the fundamental frequency is A rope

5 \mathrm{~m}

long has a total mass of

245 \mathrm{~g}

. It is stretched with a constant tension of

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wt. If it is fixed at one end and shaken by hand at the other end, what frequency of shaking will make it break up into three vibrating segments? Take

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T

is the reverberation time of an auditorium of volume

V