Skip to main content
Back to MECHANICAL PROPERTIES OF SOLIDS

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Medium
1 of 1
Application +4 | -1
The pressure of a medium is changed from 1.01×1051.01 \times {10^5} Pa to 1.165  ×1051.165\,\, \times {10^5} Pa and change in volume is 10  %10\,\,\% keeping temperature constant. The Bulk modulus of the medium is
View answer and explanation
Correct option: D
1.55  ×  1051.55\,\, \times \,\,{10^5} Pa
Option D (1.55 × 1051.55\, \times \,{10^5} Pa) is correct because it's the bulk modulus calculated using the given pressure and volume changes.

More Questions from MECHANICAL PROPERTIES OF SOLIDS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.