NEET UG PHYSICS MCQ: SEMI CONDUCTOR DEVICES

1 Easy

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Application +4 | -1

Conductivity of a photodiode starts changing only if the wavelength of incident light is less than

660 \mathrm{~nm}

. The band gap of photodiode is found to be

\left(\frac{X}{8}\right) \mathrm{eV}

. The value of

X

is (Given,

h=6.6 \times 10^{-34} \mathrm{~Js}, e=1.6 \times 10^{-19} \mathrm{C}

)

View answer and explanation

Correct option: D

Option D (15) is correct because the band gap energy can be calculated from the wavelength using

E = \frac{{hc}}{{\lambda}}

, and then solving for X.

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I = A{T^2}{e^{q/{V_L}}}

{V_L}

\sqrt{n}.

n

p - n\;

{10^{17}}\mathrm{c}{\mathrm{m}^{ - 3}}

P

{10^{16}}

\mathrm{c}{\mathrm{m}^{ - 3}}

N

kT =

{n_i} = 1.4 \times {10^{10}}

\mathrm{c}{\mathrm{m}^{ - 3}}