JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

A capacitor having a capacity of 2 pF. Electric field across the capacitor is changing with a value of

{10^{12}}\mathrm{\;V}{\mathrm{s}^{ - 1}}

. The displacement current is

View answer and explanation

Correct option: A

2\mathrm{ }A

Option A (

2\mathrm{ }A

) is correct because the displacement current is calculated using the formula

i = C\frac{{dV}}{{dt}}

, where C is the capacitance and

\frac{{dV}}{{dt}}

is the rate of change of electric field.

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