NEET UG PHYSICS MCQ: NUCLEI

The energy released in the fusion of $2 \mathrm{~kg}$ of hydrogen deep in the sun is $\mathrm{E}_{\mathrm{H}}$ and the energy released in the fission of $2 \mathrm{~kg}$ of ${ }^{235} \mathrm{U}$ is $\mathrm{E}_{\mathrm{U}}$. The ratio $\frac{\mathrm{E}_{\mathrm{H}}}{\mathrm{E}_{\mathrm{U}}}$ is approximately :

(Consider the fusion reaction as ${4}_1^1 \mathrm{H}+2 \mathrm{e}^{-} \rightarrow{ }_2^4 \mathrm{He}+2 \mathrm{v}+6 \gamma+26.7 \mathrm{~M~eV}$, energy released in the fission reaction of ${ }^{235} \mathrm{U}$ is $200 \mathrm{~M~eV}$ per fission nucleus and $\mathrm{N}_{\mathrm{A}}=6.023 \times 10^{23}$)