Nitrobenzene can be prepared from benzene by using a mixture of conc. ${\rm{HN}}{{\rm{O}}_3}$ and conc.${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$. In the mixture, nitric acid acts as a/an:

JEE CHEMISTRY MCQ: HYDROCARBONS

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Nitrobenzene can be prepared from benzene by using a mixture of conc.

\mathrm{HN}{\mathrm{O}_3}

and conc.

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

. In the mixture, nitric acid acts as a/an:

View answer and explanation

Correct option: D

Base

Option D (Base) is correct because in the nitration of benzene, nitric acid accepts a proton from sulfuric acid, acting as a base to generate the nitronium ion.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: