The angle between the curves $y = \sin x\,and\,\;y = \cos x$ is

${\tan ^{ - 1}}\left( {3\sqrt 2 } \right)$

${\tan ^{ - 1}}\left( {3\sqrt 3 } \right)$

${\tan ^{ - 1}}\left( {5\sqrt 2 } \right)$

JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The angle between the curves

y = \sin x\,and\,\;y = \cos x

View answer and explanation

Correct option: A

{\tan ^{ - 1}}\left( {2\sqrt 2 } \right)

Option A (

{\tan ^{ - 1}}( {2\sqrt 2 } )

) is correct because it represents the angle between the two curves, calculated using the slopes of the tangent lines at their intersection point.

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z