If $f\left( x \right)$ is differentiable and strictly increasing function, then the value of $\mathop {\lim }\limits_{x \to 0} \frac{{f\left( {{x^2}} \right) - f\left( x \right)}}{{f\left( x \right) - f\left( 0 \right)}}$ is

JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

f\left( x \right)

is differentiable and strictly increasing function, then the value of

\lim\limits_{x \to 0} \frac{{f\left( {{x^2}} \right) - f\left( x \right)}}{{f\left( x \right) - f\left( 0 \right)}}

View answer and explanation

Correct option: C

- 1

Option C (-1) is correct because applying L'Hopital's rule and evaluating the limit results in -1.

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