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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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The thermo emf E\mathrm{E} in volts of a certain thermocouple is found to vary with temperature difference θ\theta in ∘C{ }^{\circ} \mathrm{C} between the two junctions according to the relation E=30θ−θ215\mathrm{E}=30 \theta-\frac{\theta^2}{15}, then the neutral temperature of thermocouple is
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Correct option: B
225∘C225^{\circ} \mathrm{C}
Option B (225∘C225^{\circ} \mathrm{C}) is correct because the neutral temperature is found by setting the derivative of the thermo emf with respect to temperature difference equal to zero and solving for the temperature.

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