JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1

In young's interference experiment, if

\mathrm{I}_0

be the intensity at the central bright fringe,

\beta

be the fringe width then the intensity as the function of distance

x

from the central bright frings is:

View answer and explanation

Correct option: D

\mathrm{I}=\mathrm{I}_0 \cos ^2\left(\frac{\pi x}{\beta}\right)

Option D (

\mathrm{I}=\mathrm{I}_0 \cos ^2\left(\frac{\pi x}{\beta}\right)

) is correct because it represents the intensity as a function of distance from the central bright fringe in Young's double-slit experiment.

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