JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

Let

a_{1}, a_{2}, a_{3}, \ldots

be an A.P, such that

\frac{a_{1}+a_{2}+\ldots+a_{p}}{a_{1}+a_{2}+a_{3}+\ldots+a_{q}}=\frac{p^{3}}{q^{3}} ; p \neq q

. Then

\frac{a_{6}}{a_{21}}

is equal to:

View answer and explanation

Correct option: B

\frac{31}{121}

Option B (31/121) is correct because the ratio a6/a21 is calculated by using the given ratio of sums and properties of arithmetic progressions.

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