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JEE PHYSICS MCQ: RAY OPTICS

1 Medium

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Application +4 | -1

The focal lengths of a convex lens for red, yellow and violet rays are

100 \mathrm{~cm}, 98 \mathrm{~cm}

and

96 \mathrm{~cm}

respectively. Find the dispersive power of the material of the lens.

View answer and explanation

Correct option: C

0.041

The correct answer is C (0.041) because the dispersive power is calculated using the focal lengths for red, yellow, and violet rays and the formula

\omega = \frac{{\mu_v - \mu_r}}{{\mu_y - 1}}

.

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