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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

Calculate the average energy density of an electromagnetic wave whose electric field is oscillating with amplitude

50 \mathrm{~v} / \mathrm{m}

and frequency

5 \times 10^{10} \mathrm{~Hz}

.

View answer and explanation

Correct option: B

1.1 \times 10^{-8} \mathrm{~J} / \mathrm{m}^3

Option B (

1.1 \times 10^{-8} \mathrm{~J} / \mathrm{m}^3

) is correct because it is the average energy density calculated using the electric field amplitude.

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