Hybridization of $P$ in $PCl_5$ is

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Easy

1 of 1

Understanding +4 | -1

Hybridization of

P

PCl_5

View answer and explanation

Correct option: A

sp^3d

Option A (

sp^3d

) is correct because in

PCl_5

, the phosphorus atom is

sp^3d

hybridized, resulting in a trigonal bipyramidal geometry.

Practice All Chapter MCQs →

\mathrm{C}{\mathrm{O}_2}

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

{BF}_3

{BCl}_3

{BF}_3

{BCl}_3

{B}-X \pi