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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Analyzing +4 | -1
The reaction ‘PP’ in the following
P→dil.   H2SO4K2Cr2O7B→H3O+CH3MgBrCH3−CH3∣C∣OH−CH3P\xrightarrow[{{\text{dil}}.\,\,\,{H_2}S{O_4}}]{{{K_2}C{r_2}{O_7}}}B\xrightarrow[{{H_3}{O^ + }}]{{C{H_3}MgBr}}C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {OH} \end{array} - C{H_3}
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Correct option: A
CH3CHOHCH3{CH}_3 {CHOHCH}_3
Option A is correct because the alcohol P is oxidized to a ketone B, which then reacts with Grignard reagent to form a tertiary alcohol after hydrolysis, indicating P must be a secondary alcohol.

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