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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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A 3Β cmΓ—10Β cm3 {~cm} \times 10 {~cm} rectangular coil with number of turns 300 is placed in uniform magnetic field of strength 0.2Β T0.2 {~T}. The maximum magnetic torque acting on it when a current of 10βˆ’4Β A10^{-4} {~A} is passed through it; 
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Correct option: D
1.8Γ—10βˆ’5Nm1.8 \times 10^{-5} {Nm}
Option D (1.8Γ—10βˆ’5Nm1.8 \times 10^{-5} {Nm}) is correct because it is the maximum torque calculated using the formula Ο„=NIBAsin⁑θ\tau = NIBA \sin \theta with ΞΈ=90∘\theta = 90^{\circ}.

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