JEE MATHEMATICS MCQ: COMPOUND ANGLES

1 Easy

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Application +4 | -1

\cot \alpha=1

and

\sec \beta=-\frac{5}{3}

, where

\pi<\alpha<\frac{3 \pi}{2}

and

\frac{\pi}{2}<\beta<\pi

, then the value of

\tan (\alpha+

\beta)

and the quadrant in which

\alpha+\beta

lies, respectively are :

View answer and explanation

Correct option: A

-\frac{1}{7}

and IVth quadrant

The correct answer is A (-1/7 and IVth quadrant) because it correctly calculates the tangent of the sum of angles and identifies the correct quadrant.

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\tan \left( {A + B} \right) = p

and

\tan \left( {A - B} \right) = q

, then the value of

\tan \,\,2A

is The value of

\cos \,\,x\,\,\cos \,\,y\,\,\sin \,\,\left( {x - y} \right) + \cos \,\,y\,\,\cos \,\,z\,\,\sin \,\,\left( {y - z} \right)

+ \cos \,\,z\,\,\cos \,\,x\,\,\sin \,\,\left( {z - x} \right) + \sin \,\,\left( {x - y} \right)\sin \,\,\left( {y - z} \right)\,\,\sin \,\,\left( {z - x} \right)

, is
The sides of a triangle are

\sin \alpha, \cos \alpha

and

\sqrt{1+\sin \alpha \cos \alpha}

for some

0<\alpha<\frac{\pi}{2}

. Then, the greatest angle of the triangle is If

\tan \,\,A = 2\,\,\tan \,\,B + \cot \,\,B,\;\;\mathrm{then}\;\,2\,\,\tan \left( {A - B} \right)\mathrm{\;}

is equal to

If

A,B,C

are angles of a triangle, then the minimum value of

{\tan ^2}\,\,\frac{A}{2} + {\tan ^2}\,\,\frac{B}{2} + {\tan ^2}\,\,\frac{C}{2}

, is If

A > 0,\,\;B > 0

and

A + B = \frac{\pi }{3}

, then the maximum value of

\tan A\,\,\tan B

, is