JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

\alpha

and

\beta

are roots of the equation,

x^{2}-4 \sqrt{2} k x+2 e^{4 \ln k}-1=0

for some

k

, and

\alpha^{2}+\beta^{2}=66

, then

\alpha^{3}+\beta^{3}

is equal to:

View answer and explanation

Correct option: D

-280 \sqrt{2}

Option D (

-280 \sqrt{2}

) is correct because solving for k and substituting it into the expression for

\alpha^{3}+\beta^{3}

yields

-280 \sqrt{2}

More Questions from QUADRATIC EQUATIONS

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{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

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