JEE MATHEMATICS MCQ: PERMUTATIONS

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How many numbers lying between 10 and 1000 can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition of digits is allowed)?

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Correct option: B

810

Option B (810) is correct because it calculates the total number of 2-digit and 3-digit numbers that can be formed using the given digits with repetition allowed.

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