JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Application +4 | -1

Consider a uniform wire of mass

M

and length

L

. It is bent into a semicircle. Its moment of inertia about a line perpendicular to the plane of the wire passing through the centre is

View answer and explanation

Correct option: C

\frac{{M{L^2}}}{{{\pi ^2}}}

Option C (

\frac{{M{L^2}}}{{{\pi ^2}}}

) is correct because the moment of inertia of a semicircular wire about an axis perpendicular to the plane and passing through the center is

MR^2

, where R is the radius of the semicircle.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)