Back to ELECTRIC FIELDS AND CHARGES

JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Medium

1 of 1

Application +4 | -1

Find the ratio of the magnitude of the electric force to the gravitational force acting between two protons.

View answer and explanation

Correct option: A

1.24 \times 10^{36}

Option A (

1.24 \times 10^{36}

) is correct because it is the ratio of electric force to gravitational force calculated using the respective formulas.

More Questions from ELECTRIC FIELDS AND CHARGES

Practice All Chapter MCQs →

Assertion:- Electric field lines do not cut at any point.
Reason:- At any point, there is only one direction of electric field. Statement-I: A positive point charge is brought in an electric field, the electric field at neary by point will increase

Statement-II: Electric field produced by charge may favour the existing electric filed Two particles having equal mass and charge
are separated by a distance

r.

The force(s) they
experience is (are) Statement-I: No 2 electric lines of force can intersect each other

Statement-II: tangent at any point of electric line of force gives the direction of electric field A force of

4N

is acting between two charges in air if the space between them is completely filled with glass

\left( {{\varepsilon _r} = 8} \right)

, then the new force will be ……

N

An electron is placed at centre of a conducting sphere of radius 0.2 metre having charge

5 \times {10^{ - 2}}

coulomb. The force of on the electron is ________ N