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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The radius of an orbit of H – atom is

4.77 \times {10^{ - 10}}m

. Then the angular momentum of an electron in this orbit is

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Correct option: B

1.5h/\pi

Option B (

1.5h/\pi

) is correct because the radius is used to determine the orbit number (n=3), and then the angular momentum is calculated using the formula

L = nh/2\pi

.

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