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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let f(x)=∫1x2−t2dtf(x)=\int\limits_{1}^x \sqrt{2-t^2} d t. Then the real roots of the equation x2−f′(x)=0x^2-f^{\prime}(x)=0 are
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Correct option: A
±1\pm 1
Option A (±1\pm 1) is correct because these values satisfy the equation x2=2−x2x^2 = \sqrt{2-x^2} derived from the given conditions.

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