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JEE MATHEMATICS MCQ: ELLIPSE

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The equation of a diameter conjugate to a diameter y=baxy = \frac{b}{a}x of the ellipse x2a2+y2b2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1 is
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Correct option: A
y=−baxy = - \frac{b}{a}x
Option A (y=−baxy = - \frac{b}{a}x) is correct because conjugate diameters of an ellipse satisfy the condition m1m2=−b2a2{m_1}{m_2} = - \frac{{{b^2}}}{{{a^2}}}.

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