The radii of ${\rm{F}},{{\rm{F}}^ - },{\rm{O}}$ and ${{\rm{O}}^{2 - }}$ are in the order of:

${{\rm{O}}^{2 - }} > {{\rm{F}}^ - } > O > F$

${{\rm{O}}^{2 - }} > {{\rm{F}}^ - } > F > O$

${{\rm{F}}^ - } > {{\rm{O}}^{2 - }} > F > O$

${{\rm{O}}^{2 - }} > O > {{\rm{F}}^ - } > F$

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NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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The radii of

\mathrm{F},{\mathrm{F}^ - },\mathrm{O}

and

{\mathrm{O}^{2 - }}

are in the order of:

View answer and explanation

Correct option: D

{\mathrm{O}^{2 - }} > {\mathrm{F}^ - } > O > F

Option D (

{\mathrm{O}^{2 - }} > {\mathrm{F}^ - } > O > F

) is correct because anions are larger than their neutral atoms, and for isoelectronic species, the species with lower nuclear charge has a larger radius.

NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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