Quantum numbers for some electrons are given below A : $n=4, I=1\qquad$ B : $n=4, I=0\qquad$ C: $n=3, I=2\qquad$ D: $n=3, I=1$ The correct increasing order of energy of electrons

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Quantum numbers for some electrons are given below

A :

n=4, I=1\qquad

B :

n=4, I=0\qquad

n=3, I=2\qquad

n=3, I=1

The correct increasing order of energy of electrons

View answer and explanation

Correct option: C

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Option C (D

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A) is correct because it represents the increasing order of energy based on the (n+l) rule and the n value when (n+l) is the same.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.