NEET UG PHYSICS MCQ: MAGNETISM AND MATTER

1 Hard

1 of 1

Application +4 | -1

A vibration magnetometer placed in magnetic meridian has small bar magnet. The magnet executes oscillations with a time period of

2 \, \mathrm{sec}

in earth's horizontal magnetic field of

36 \, \mu \mathrm{T}

. When a horizontal magnetic field '

B

' is produced opposite to the earth's field by placing a current carrying wire, the new time period of magnet is

6 \, \mathrm{sec}

. Then value of '

{B}

' is:

View answer and explanation

Correct option: D

32 \mu \mathrm{T}

Option D (

32 \mu \mathrm{T}

) is correct because it involves calculating the magnetic field produced by the wire using the time periods of oscillation.

More Questions from MAGNETISM AND MATTER

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\vec A = 2\vec i - 3\vec j + 6\vec k\,{m^2}

\vec B = - 3\vec i + \vec j + 2\vec k\,\left( {Wb/{m^2}} \right)

250\;joule

10\;kg

50\;Hz

7.5\;gm/c{m^3}

M

B