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JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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Analyzing +4 | -1
The number of asymmetric carbon atoms and the number of optical isomers in CH3(CHOH)2COOH\mathrm{C}{\mathrm{H}_3}{\left( {\mathrm{CHOH}} \right)_2}\mathrm{COOH} are respectively :
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Correct option: C
2 and 4
Option C (2 and 4) is correct because the compound has two asymmetric carbon atoms, leading to 22=42^2 = 4 stereoisomers.

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