If $\mathop \sum \limits_{i = 1}^{18} \left( {{x_i} - 8} \right) = 9\;and\;\mathop \sum \limits_{i = 1}^{18} {\left( {{x_i} - 8} \right)^2} = 45$, then the standard derivation of ${x_1},{x_2}, \ldots ,{x_{18}}$ is

JEE MATHEMATICS MCQ: STATISTICS

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Application +4 | -1

\sum \limits_{i = 1}^{18} \left( {{x_i} - 8} \right) = 9\;and\;\sum \limits_{i = 1}^{18} {\left( {{x_i} - 8} \right)^2} = 45

, then the standard derivation of

{x_1},{x_2}, \ldots ,{x_{18}}

View answer and explanation

Correct option: C

\frac{3}{2}

Option C (

\frac{3}{2}

) is correct because the standard deviation can be calculated using the given sums.

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{x_1},{x_2}, \ldots ,{x_n}

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