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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
Sum of the series 0.5+0.55+0.555+…0.5+0.55+0.555+\ldots upto nn terms is
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Correct option: D
59[n−19(1−110n)]\frac{5}{9}\left[n-\frac{1}{9}\left(1-\frac{1}{10^n}\right)\right]
Option D is correct because the sum of the series can be expressed and simplified to 59[n−19(1−110n)]\frac{5}{9}\left[n-\frac{1}{9}\left(1-\frac{1}{10^n}\right)\right].

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