JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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According to Heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass

9.1 \times 10^{-31} {~kg}

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Correct option: C

5.8 \times 10^{-5} {~m}^2 {~s}^{-1}

Option C (

5.8 \times 10^{-5} \mathrm{~m}^2 \mathrm{~s}^{-1}

) is correct because it is calculated using Heisenberg's uncertainty principle.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.