When ${{\rm{K}}_2}{\rm{C}}{{\rm{r}}_2}{{\rm{O}}_7}$ is converted into ${{\rm{K}}_2}{\rm{Cr}}{{\rm{O}}_4},$ the change in oxidation number of chromium is

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

When

{\mathrm{K}_2}\mathrm{C}{\mathrm{r}_2}{\mathrm{O}_7}

is converted into

{\mathrm{K}_2}\mathrm{Cr}{\mathrm{O}_4},

the change in oxidation number of chromium is

View answer and explanation

Correct option: A

Option A (0) is correct because when K2Cr2O7 is converted to K2CrO4, the oxidation state of chromium remains +6 in both compounds.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.