JEE CHEMISTRY MCQ: REDOX REACTIONS

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Understanding +4 | -1

Standard reduction potentials at

25^{\circ} \mathrm{C}

\mathrm{Li}^{+} / \mathrm{Li}, \mathrm{Ba}^{2+} / \mathrm{Ba}, \mathrm{Na}^{+} / \mathrm{Na}

and

\mathrm{Mg}^{2+} / \mathrm{Mg}

are

-3.05,-2.90,-2.71

and

-2.37

volt respectively. Which one of the following is the strongest oxidizing agent?

View answer and explanation

Correct option: B

\mathrm{Mg}^{2+}

Option B (

\mathrm{Mg}^{2+}

) is correct because the strongest oxidizing agent is the one with the highest reduction potential.

More Questions from REDOX REACTIONS

Practice All Chapter MCQs →

\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.