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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The sum⁡312+512+22+712+22+32+…\operatorname{sum} \frac{3}{1^{2}}+\frac{5}{1^{2}+2^{2}}+\frac{7}{1^{2}+2^{2}+3^{2}}+\ldots upto 11 -terms is:
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Correct option: C
112\frac{11}{2}
Option C (112\frac{11}{2}) is correct because the series can be expressed as a telescoping series, allowing for simplification and direct calculation.

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