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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
Let a1=1,a2=1+a1,a3=1+a1a2,…,an+1=1+a_1=1, a_2=1+a_1, a_3=1+a_1 a_2, \ldots, a_{n+1}=1+ a1a2…ana_1 a_2 \ldots a_n. Then ∑n=1=1an=\sum\limits_{{n=1}}^{=} \frac{1}{a_n}=
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Correct option: C
2
Option C (2) is correct because the infinite sum of the reciprocals of the recursively defined sequence converges to 2.

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