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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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C6H5CH=CHCHO⟶XC6H5CH=CHCH2OH\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CHCHO} \stackrel{\mathrm{X}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CHCH}_2 \mathrm{OH} In the above sequence X\mathrm{X} can be :
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Correct option: B
NaBH4\mathrm{NaBH}_4
Option B (NaBH4\mathrm{NaBH}_4) is correct because NaBH4NaBH_4 is a selective reducing agent that reduces aldehydes to primary alcohols without affecting carbon-carbon double bonds.

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