JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

p

is the length of the perpendicular from a facus upon the tangent at any point

p

of the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1

and

r

is the distance of

p

from the focus, then

\frac{{2a}}{r} - \frac{{{b^2}}}{{{p^2}}}

is equal to

View answer and explanation

Correct option: C

Option C (1) is correct because, after substituting and simplifying, the expression equals 1.

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\frac{x^2}{144}+\frac{y^2}{81}=1

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\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

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P

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Q

R

N P

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P

O