NEET UG PHYSICS MCQ: ALTERNATING CURRENT

1 Hard

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Application +4 | -1

A pure resistive circuit element

X

when connected to an AC supply of peak voltage

200 \mathrm{~V}

gives a peak current of

5 \mathrm{~A}

which is in phase with the voltage. A second circuit element

\mathrm{Y}

, when connected to the same AC supply also gives the same value of peak current but the current lags behind by

90^{\circ}

. If the series combination of

\mathrm{X}

and

\mathrm{Y}

is connected to the same supply, the rms valus of current is

View answer and explanation

Correct option: A

\frac{5}{\sqrt{2}} \mathrm{~A}

Option A (

\frac{5}{\sqrt{2}} \mathrm{~A}

) is correct because it is calculated by finding the resistance and reactance, then the impedance, and finally the RMS current.

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