If $\log \left( {x + y} \right) = \log 2 + \frac{1}{2}\log x + \frac{1}{2}\log y,\;{\rm{then}}$

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

\log \left( {x + y} \right) = \log 2 + \frac{1}{2}\log x + \frac{1}{2}\log y,\;\mathrm{then}

View answer and explanation

Correct option: B

x - y = 0

Option B (

x - y = 0

) is correct because it is the simplified form of the given logarithmic equation, indicating that x and y are equal.

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\frac{3}{4}