Decreasing order of $C{\rm{ }}-{\rm{ }}C$ bond length is (I) ${{\rm{C}}_2}{{\rm{H}}_4}$ (II) ${{\rm{C}}_2}{{\rm{H}}_2}$ (III) ${{\rm{C}}_6}{{\rm{H}}_6}$ (IV) ${{\rm{C}}_2}{{\rm{H}}_6}$

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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Medium

1 of 1

Understanding +4 | -1

Decreasing order of

C\mathrm{ }-\mathrm{ }C

bond length is
(I)

{\mathrm{C}_2}{\mathrm{H}_4}

(II)

{\mathrm{C}_2}{\mathrm{H}_2}

(III)

{\mathrm{C}_6}{\mathrm{H}_6}

(IV)

{\mathrm{C}_2}{\mathrm{H}_6}

View answer and explanation

Correct option: A

\mathrm{IV} > III > I > II

Option D (IV > III > I > II) is correct because single bonds are longer than double bonds, which are longer than triple bonds, and the bond length in benzene is intermediate between single and double bonds.

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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