The number of stereoisomers of compound ${\rm{C}}{{\rm{H}}_3}-{\rm{CH}} = {\rm{CH}}-{\rm{CHBr}}-{\rm{C}}{{\rm{H}}_3}$ would be:

NEET UG CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

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The number of stereoisomers of compound

\mathrm{C}{\mathrm{H}_3}-\mathrm{CH} = \mathrm{CH}-\mathrm{CHBr}-\mathrm{C}{\mathrm{H}_3}

would be:

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Correct option: D

Option D (4) is correct because the compound has one chiral center and exhibits cis/trans isomerism due to the double bond, resulting in 2 x 2 = 4 stereoisomers.

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