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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If the sum of the first ten terms of the series (135)2+(225)2+(315)2+42+(445)2+…\left(1 \frac{3}{5}\right)^2+\left(2 \frac{2}{5}\right)^2+\left(3 \frac{1}{5}\right)^2+4^2+\left(4 \frac{4}{5}\right)^2+\ldots is 165 m\frac{16}{5} \mathrm{~m}, then mm equal to
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Correct option: D
101
Option D (101) is correct because the sum of the given series can be simplified and calculated using the formula for the sum of squares of natural numbers.

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