JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Bond dissociation on energy of

\mathrm{Br}_2

200 \mathrm{~kJ} / \mathrm{mole}

. The longest wavelength of photon that can break this bond would be

\left(N_{\mathrm{A}} \times h c=0.12 \mathrm{~J}\right)

View answer and explanation

Correct option: C

6.0 \times 10^{-7} \mathrm{~m}

Option C (

6.0 \times 10^{-7} \mathrm{~m}

) is correct because it is the longest wavelength of a photon that can break the

Br_2

bond, calculated using the energy-wavelength relationship.

More Questions from STRUCTURE OF ATOM

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.