JEE CHEMISTRY MCQ: REDOX REACTIONS

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Analyzing +4 | -1

Given:

\begin{aligned} & {E}_{\frac{1}{2} {Cl}_2 / {Cl}^{-}}^{{o}}=1.36 {~V}, {E}_{{Cr}^{3+} / {Cr}}^{{o}}=-0.74 {~V}, \\ & {E}_{{Cr}_2 {O}_7^{2-} / {Cr}^{3+}}^{{o}}=1.33 {~V}, {E}_{{MnO}_4^{-} / {Mn}^{2+}}^{{o}}=1.51 {~V} \end{aligned}

The correct order of reducing power of the species

\left({Cr}, {Cr}^{3+}, {Mn}^{2+}\right.

and

\left.{Cl}^{-}\right)

will be

View answer and explanation

Correct option: A

{Mn}^{2+}<{Cl}^{-}<{Cr}^{3+}<{Cr}

The correct answer is A (

{Mn}^{2+}<{Cl}^{-}<{Cr}^{3+}<{Cr}

) because the reducing power increases as the reduction potential decreases.

More Questions from REDOX REACTIONS

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.